x^2=3.29-3.29x

Solution for x^2=3.29-3.29x equation:

x^2=3.29-3.29x

We move all terms to the left:

x^2-(3.29-3.29x)=0

We add all the numbers together, and all the variables

x^2-(-3.29x+3.29)=0

We get rid of parentheses

x^2+3.29x-3.29=0

a = 1; b = 3.29; c = -3.29;
Δ = b2-4ac
Δ = 3.292-4·1·(-3.29)
Δ = 23.9841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.29)-\sqrt{23.9841}}{2*1}=\frac{-3.29-\sqrt{23.9841}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.29)+\sqrt{23.9841}}{2*1}=\frac{-3.29+\sqrt{23.9841}}{2}
$